P n. . Combinations with Repetition on dCode.fr [online website], retrieved on 2023-03-05, https://www.dcode.fr/combinations-with-repetitions, combination,repetition,repeats,tuple,uple,generator, https://www.dcode.fr/combinations-with-repetitions. Not the answer you're looking for? So $$ \binom{0}{k} = 0 $$, By convention 0 choose 0 is 1: $$ \binom{0}{0} = 1 $$, // pseudo codestart count_combinations( k , n ) { if (k = n) return 1; if (k > n/2) k = n-k; res = n-k+1; for i = 2 by 1 while i < = k res = res * (n-k+i)/i; end for return res;end// language Cdouble factorial(double x) { double i; double result=1; if (x >= 0) { for(i=x;i>1;i--) { result = result*i; } return result; } return 0; // error}double count_combinations(double x,double y) { double z = x-y; return factorial(x)/(factorial(y)*factorial(z));}// VBAFunction Factorial(n As Integer) As Double Factorial = 1 For i = 1 To n Factorial = Factorial * i NextEnd FunctionFunction NbCombinations (k As Integer, n As Integer) As Double Dim z As Integer z = n - k NbCombinations = Factorial(n) / (Factorial(k) * Factorial(z))End Function, // javascriptfunction combinations(a) { // a = new Array(1,2) var fn = function(n, src, got, all) { if (n == 0) { if (got.length > 0) { all[all.length] = got; } return; } for (var j = 0; j < src.length; j++) { fn(n - 1, src.slice(j + 1), got.concat([src[j]]), all); } return; } var all = []; for (var i=0; i < a.length; i++) { fn(i, a, [], all); } all.push(a); return all;}. What is the algorithm to generate combinations? In this calculator I get 126 which is not correct. Permutation and Combination Calculator. b)One specific individual must be picked on the advisory group? "Object input 1" + "Object input 2" + "Object input 3" and so on. Arrangements with Repetitions Generator Formula for Permutation with Repetition: The formula for permutations with repetition objects is as follows: Here, n1 is the identical elements of type 1, n How can I check before my flight that the cloud separation requirements in VFR flight rules are met? = 6, = 3. by Putting these values in above formula, we have: Combination calculator helps you to generate combination without repetition. You can find yourself to cope with this competition as there are many online combination generator available. Combination Generator or Pair Generator is an online tool to pair and generate all possible (unique) combinations from one or two lists of items or names which can be sorted by group, random or by input. Solution: Calculates the count of combinations without repetition or combination number. Similarly, iterate with all the list elements one by one by recursion of the remaining list. If n is large, you can use bitset. Combination without repetition: Total combinations = (r + n - 1)! Identify those arcade games from a 1983 Brazilian music video. $\begingroup$ This provides a way to find the number of possible combinations without repetition, but it doesn't provide a way to actually . However I want to filter out the repetitive number combinations like e.g. Number of rows : (7*6*5)/ (3*2*1) = 35. Let's consider the set $$A=\{a,b,c,d,e\}$$ of $$5$$ elements. So int is efficient. =. Example: A,B,C items are shuffled in 6 couples of 2 items: A,A A,B A,C B,B B,C, C,C. rev2023.3.3.43278. E.g. What is the algorithm for counting combinations? In the previous example, $$n = 5$$. For example, if you have a set from 3 elements, {A, B, C}, the all possible combinations of size 2 will be {A,B}, {A,C} and {B,C}. Looking for an expanded method to generate combinations of words in excel for any number of combination. = 6, = 3. Combinations generator. We can count the number of combinations without repetition using the nCr formula, where n is 3 and r is 2. Just type the items. The number of combinations n=49, k=6 is 13983816 - calculation result using a combinatorial calculator. Numbers of different groups that can be formed by selecting some or all the items are called combinations of those numbers. / p! After entering one or two list of items, you will see the possible number of combinations. The selection of items from a collection in a way that the order of the selection does not matter. Without repetition, there would be only 3 couples A,B, A,C et B,C. Clear up math questions . September 09, 2020. a) In what number of these hands are there. You can also create combinations from one list of items which will create pairs or combinations. What we need to know is how many permutations of these objects are there. Thanks for your support. The following program will produce the combinations in that order. and all data download, script, or API access for "Combination N Choose K" are not public, same for offline use on PC, mobile, tablet, iPhone or Android app! For this circumstance, when you circulate a once-over, it isn't noteworthy who was picked first. Click on Go to generate multiple sets of random numbers. To be more clear: If the input number is 4 then i want to use digits 1-4 and generate all the possible combinations of digits (from 1-digit combinations to 4-digit combinations) without digit repetitions. Number combination generator or letter combination generator. An example is given of the manual conversion of a push-style generator into a pull-style generator, without language constructs like Limited Continuations (Scala) or yield (Python and ES6). The formula to determine the number of possible combinations is as follows: C(n, r) = n! Colloquially, we can say that permutation is a mixing of elements. Combinations. A combination is written by the letters nCr, where n is the number of elements of a set, and r is the number of elements we are going to pick, where r cannot be major than n, because this would produce an error. It's more like, Great short solution, is there a way to change it such that it generates the combinations in order? Thank you! Then you select a digit e from ({0, 1, 2, 3, 4, 5, 6, 7, 8, 9}-d). . In the above case suppose you take a photograph of 11 players, then even by changing the position of one player we will get a different photo. So, the answer is. algorithm for generating number combinations without repetition, compprog.wordpress.com/2007/10/17/generating-combinations-1, How Intuit democratizes AI development across teams through reusability. Thank you! Can carbocations exist in a nonpolar solvent? This combinations calculator generates all possible combinations of m elements from the set of n elements. Output Box - Combinations will display here. Similarly, for every iteration of the inner for loop, the inner most for loop executes 3 times. Here is a program that generates combinations of numbers. (1,2)(1,3)(1,4)(1,5)(2,3)(2,4)(2,5)(3,4)(3,5)(4,5), (1,2)(1,3)(1,4)(1,5)(1,6)(2,3)(2,4)(2,5)(2,6)(3,4)(3,5)(3,6)(4,5)(4,6)(5,6), (1,2)(1,3)(1,4)(1,5)(1,6)(1,7)(2,3)(2,4)(2,5)(2,6)(2,7)(3,4)(3,5)(3,6)(3,7)(4,5)(4,6)(4,7)(5,6)(5,7)(6,7), (1,2)(1,3)(1,4)(1,5)(1,6)(1,7)(1,8)(2,3)(2,4)(2,5)(2,6)(2,7)(2,8)(3,4)(3,5)(3,6)(3,7)(3,8)(4,5)(4,6)(4,7)(4,8)(5,6)(5,7)(5,8)(6,7)(6,8)(7,8), (1,2)(1,3)(1,4)(1,5)(1,6)(1,7)(1,8)(1,9)(2,3)(2,4)(2,5)(2,6)(2,7)(2,8)(2,9)(3,4)(3,5)(3,6)(3,7)(3,8)(3,9)(4,5)(4,6)(4,7)(4,8)(4,9)(5,6)(5,7)(5,8)(5,9)(6,7)(6,8)(6,9)(7,8)(7,9)(8,9), (1,2,3)(1,2,4)(1,2,5)(1,3,4)(1,3,5)(1,4,5)(2,3,4)(2,3,5)(2,4,5)(3,4,5), (1,2,3)(1,2,4)(1,2,5)(1,2,6)(1,3,4)(1,3,5)(1,3,6)(1,4,5)(1,4,6)(1,5,6)(2,3,4)(2,3,5)(2,3,6)(2,4,5)(2,4,6)(2,5,6)(3,4,5)(3,4,6)(3,5,6)(4,5,6), (1,2,3)(1,2,4)(1,2,5)(1,2,6)(1,2,7)(1,3,4)(1,3,5)(1,3,6)(1,3,7)(1,4,5)(1,4,6)(1,4,7)(1,5,6)(1,5,7)(1,6,7)(2,3,4)(2,3,5)(2,3,6)(2,3,7)(2,4,5)(2,4,6)(2,4,7)(2,5,6)(2,5,7)(2,6,7)(3,4,5)(3,4,6)(3,4,7)(3,5,6)(3,5,7)(3,6,7)(4,5,6)(4,5,7)(4,6,7)(5,6,7), (1,2,3,4)(1,2,3,5)(1,2,4,5)(1,3,4,5)(2,3,4,5), (1,2,3,4)(1,2,3,5)(1,2,3,6)(1,2,4,5)(1,2,4,6)(1,2,5,6)(1,3,4,5)(1,3,4,6)(1,3,5,6)(1,4,5,6)(2,3,4,5)(2,3,4,6)(2,3,5,6)(2,4,5,6)(3,4,5,6), (1,2,3,4)(1,2,3,5)(1,2,3,6)(1,2,3,7)(1,2,4,5)(1,2,4,6)(1,2,4,7)(1,2,5,6)(1,2,5,7)(1,2,6,7)(1,3,4,5)(1,3,4,6)(1,3,4,7)(1,3,5,6)(1,3,5,7)(1,3,6,7)(1,4,5,6)(1,4,5,7)(1,4,6,7)(1,5,6,7)(2,3,4,5)(2,3,4,6)(2,3,4,7)(2,3,5,6)(2,3,5,7)(2,3,6,7)(2,4,5,6)(2,4,5,7)(2,4,6,7)(2,5,6,7)(3,4,5,6)(3,4,5,7)(3,4,6,7)(3,5,6,7)(4,5,6,7), (1,2,3,4,5)(1,2,3,4,6)(1,2,3,5,6)(1,2,4,5,6)(1,3,4,5,6)(2,3,4,5,6), (1,2,3,4,5)(1,2,3,4,6)(1,2,3,4,7)(1,2,3,5,6)(1,2,3,5,7)(1,2,3,6,7)(1,2,4,5,6)(1,2,4,5,7)(1,2,4,6,7)(1,2,5,6,7)(1,3,4,5,6)(1,3,4,5,7)(1,3,4,6,7)(1,3,5,6,7)(1,4,5,6,7)(2,3,4,5,6)(2,3,4,5,7)(2,3,4,6,7)(2,3,5,6,7)(2,4,5,6,7)(3,4,5,6,7). Generate objects into combinations of which will produce sets. Such as 1,2,3,4,12,13,23,14,24,34,123,124,134,234,1234. Enter the estimation of "n" in the first field, Enter the estimation of r in the second field. Whats the grammar of "For those whose stories they are"? x (n - 1)!) Before we start discussing about the implementation we will go through the basic definitions of Combinations. satish1988 . Free online combinations calculator and permutations calculator for Repetition isn't allowed because Susan can't be on the committee twice (even if she. At the end of 3 iteration of outer most for loop, all the combinations of numbers 1, 2 and 3 are generated. Find how many ways a cricket team having 11 players can be formed from 15 high-class payers available? 464 Math Teachers. I honestly not sure it is standard-portable (I think it is, but would need to read up a bit). = 3! Please, check our dCode Discord community for help requests!NB: for encrypted messages, test our automatic cipher identifier! Combinations with Repetition. (1+1)2 (2+1)3 (3+1)4 = 2 3 4 Then we check the last element (i = 3). Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. The combination formula is n P r means the number of Combination without repetition of "n" things take "r" at a time. Select odd only, even only, half odd and half even or custom odd/even numbers. Combinations without repetition. list 1: colleagues with junior skills, list 2: colleagues with senior skills. I have a list of 50+ words that would need to be generated out to a potential of 10+ string combinations without repetition. We can check in the previous list that there are $$10$$ sets of $$3$$ elements, indeed. Example: Calculate the number of combinations of (50 choose 5) = 2 118 760, and multiply by (11 choose 2) = 55 for a total of 116 531 800 combinations. # combinations = n! All combination can be unique, random, sorted by input and/or grouped by one list.if(typeof ez_ad_units!='undefined'){ez_ad_units.push([[580,400],'commentpicker_com-large-mobile-banner-1','ezslot_5',126,'0','0'])};__ez_fad_position('div-gpt-ad-commentpicker_com-large-mobile-banner-1-0'); You can also create combinations from one list of items which will create pairs or combinations. The entire sequence goes. Their count is: C k(n)= ( kn+k 1) = k!(n1)!(n+k1)! Permutation generator without repetition - To calculate the number of permutations - nPr: Use the permutation without repetition formula: nPr= n!/(n - r)!. Combinations. The copy-paste of the page "Combination N Choose K" or any of its results, is allowed as long as you cite dCode! For every iteration of outer most for loop, the inner for loop executes 3 times. Yes, there does exist such a way. Combinations are subsets of items taken from a larger set of items. Please note, in this use case: "word1 word2" and "word2 word1", this would be considered a repetition. To generate larger lists, dCode can generate them upon (paid) request. Take a example:1010(2)={4,2} 1111(2)={4,3,2,1}. The "Keyword Combination Generator" found in the link below hits on the basic concept, but it only allows up to four combinations and it's output has repetition. You can also select the option to create combinations with 3 items per combination. Select whether order of the numbers withing a combination matters or not. i put in excel every combination (one by one, put every single combination with "duplicate values" turned ON) possible and I get 1080 different combinations. Perhaps better, say we try to do the same thing in base 4. Reminder : dCode is free to use. Generate all possible combinations of. This calculator can be used to generate all types of permutations from n to m elements without repetitions. The combination is a method used is statistics, which consist in finding the ways we can pick some elements from a data set. If you want to output the answer as the order of giving, just make them string and put these string in vector and sort. It's messy and uses terrible variable names, but seems to work for me. But it could be rewritten in any other language. You can generate all possible combinations from a single list of items. I fixed the output and i added a better explanation, Ah, so you're trying to modify the program you found at. Or do you want them in numerical order? . Looking for random numbers for research or sampling? Is it plausible for constructed languages to be used to affect thought and control or mold people towards desired outcomes? This is when the elements of a set can be repeated, to clarify this type, here is an example: A person goes to a candy shop, where there are 10 different flavors of candy, but this person is only going to take 4, one for each one of his children, this is an example of combination with repetition, because although there are 10 different flavors, anything disallows this person to pick the same flavor twice, trice or even four times. In this statistics and probability video, I go over how to calculate combinations without replacement (repetition). Where, n is the total number in the dataset. A combination without repetition of objects from is a way of selecting objects from a list of .The selection rules are: the order of selection does not matter (the same objects selected in different orders are regarded as the same combination); We can count the number of combinations without repetition using the nCr formula, where n is 3 and r is 2 . Item combinations with repetition consist in generating the list of all possible combinations with elements that can be repeated. For the complete learning & practice of permutation, find our permutations calculator. Example 3: A man will go on a trip for 3 days, so he will take with him 3 shirts, if he has 7 shirts, how many combination of shirts can he take. . a bug ? Permutations calculator without repetition - It may also be the case that we are faced with a permutation without repetition. r! Select whether you want unique numbers or if the numbers may repeat. The calculation of the combinations generates an exponential number of values and the generator requires large calculation power on servers, these generations have therefore a cost (ask for a quote). 2015 . Solve Now. Your question is not very clear. That's only a ~15% reduction, but with a bigger k, I suppose it could get reduced more. Then list all the other numbers beneath them with the condition that for all numbers e and f, and with d held constant, the digits for e and f follow the natural number sequence down the column. }=10$$$ Enter a custom list Get Random Combinations It may take a while to generate large number of combinations. By Developing 100+ online Calculators and Converters for Math Students, Engineers, Scientists and Financial Experts, calculatored.com is one of the best free calculators website. By clicking Post Your Answer, you agree to our terms of service, privacy policy and cookie policy. And then, Jesus is the son of God, which was sent to die so everybody that believes in him has eternal life. That is, combination here refers to the combination of n things taken m at a time without repetition. Combination N Choose K on dCode.fr [online website], retrieved on 2023-03-05, https://www.dcode.fr/combinations. Why do many companies reject expired SSL certificates as bugs in bug bounties? Mathematics Stack Exchange is a question and answer site for people studying math at any level and professionals in related fields. . (n r)! Tools provided as-is, without warranty of any kind and used at your own risk. The program can easily be extended. I could obtain all combinations of 3 digits without repetition by counting up from 000 to 999, and then removing all numbers with duplicate digits, but this seems inefficient. Split up your exercises where you have 2 categories, e.g. I forgot the "password". The generator for unordered combinations without repetition for instance is designed such that the algorithm favours combinations from elements from the . So, there are 2^n different set in total. But when n>30,it may not be terminates in hours. What is the purpose of non-series Shimano components? Why do academics stay as adjuncts for years rather than move around? 1 2 3 Combinations generator Determine how many numbers you want to choose from the original set. Formula used by Combination Calculator. In Permutation the order is essential. This combinations calculator generates all possible combinations of m elements from the set of n elements. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. Cheers! What is the purpose of non-series Shimano components? 1 2 1 3 2 3. Why? Past n = 10 you are going to need semicolons! . Generated 4 combinations. The number of combinations with repeats of $ k $ items among $ N $ is equal to the number of combinations without repeats of $ k $ items among $ N + k - 1 $. (n-r)! Example: pattern c,* means that the letter c must be first (anything else can follow) The description of the algorithm used by the generator can be found below the calculator. ''+i+j+k is a string in JavaScript, so the output is: $012, 013, 014, 015, 016, 017, 018, 019, 023, 024, 025, 026, 027, 028, 029, 034, 035, 036, 037, 038, 039, 045, 046, 047, 048, 049, 056, 057, 058, 059, 067, 068, 069, 078, 079, 089, 123, 124, 125, 126, 127, 128, 129, 134, 135, 136, 137, 138, 139, 145, 146, 147, 148, 149, 156, 157, 158, 159, 167, 168, 169, 178, 179, 189, 234, 235, 236, 237, 238, 239, 245, 246, 247, 248, 249, 256, 257, 258, 259, 267, 268, 269, 278, 279, 289, 345, 346, 347, 348, 349, 356, 357, 358, 359, 367, 368, 369, 378, 379, 389, 456, 457, 458, 459, 467, 468, 469, 478, 479, 489, 567, 568, 569, 578, 579, 589, 678, 679, 689, 789$. For more details regarding this combination generator without repetition, see this complete combination tutorial. Problem : To generate all Combinations of a set of distinct elements. Recovered from https://www.sangakoo.com/en/unit/combinations-without-repetition, https://www.sangakoo.com/en/unit/combinations-without-repetition. Without repetition, there would be only 3 couples A,B, A,C et B,C. A simple example of the output of the combination generator with a list of letters and list of numbers. 3 different ways. Also provide your valuable feedback so that we could constantly improve. are not represented. We can count the number of combinations without repetition using the nCr formula, where n is 3 and r is 2. AC Op-amp integrator with DC Gain Control in LTspice, Euler: A baby on his lap, a cat on his back thats how he wrote his immortal works (origin?). $$$\displaystyle C_{5,3}=\binom{5}{3} = \frac{5!}{3!(5-3)! Browse other questions tagged, Where developers & technologists share private knowledge with coworkers, Reach developers & technologists worldwide. (n-r)!r! The "no" rule which means that some items from the list must not occur together. That's right.And that's because i tried everything else i could think.. For solving the specific problem the OP is having, this is wonderful. Our combination generator without repetition is a tool that helps you not only determine the number of combinations, but it also shows the possible sets you can make with every single Combination. Optional; the default random source will be used if null. Our options are: RG, RP and GP. We are going to see what the different combinations without repetition of these $$5$$ elements are: In this example all of the combinations could have been written. Object Input Box - Enter objects to combine with each on a new line. 52 Cards Choose 5 All grouped by list 2 (random): "A - 1 | B - 1" & "A - 2 | B - 2". What is the point of Thrower's Bandolier? To get a list of combinations with a guaranteed minimum of numbers (also called reduced lottery draw), dCode has a tool for that: To draw random numbers (Lotto, Euromillions, Superlotto, etc.). There are also two types of combinations (remember the order does not matter now): Repetition is Allowed: such as coins in your pocket (5,5,5,10,10) No Repetition: such as lottery numbers (2,14,15,27,30,33) 1. Staging Ground Beta 1 Recap, and Reviewers needed for Beta 2, Generate combinations of integers by least sum, Algorithm to return all combinations of k elements from n. What is the best algorithm for overriding GetHashCode? This article will be about The combination and when is it used, the types of combination, with formulas and examples of both types of combination. 3.0.4208.0, Combinatorics combinations, arrangements and permutations. Combination generator. All Combinations Without Repetitions. Combinations without repetition of $$5$$ elements taken $$5$$ at a time: The only group of $$5$$ elements that it is possible to form from the elements of $$A$$ is $$abcde$$. r! When selecting a specific number of combination, it will always be a random combination. It's possible to generate all possible combinations of 3 digits by counting up from 000 to 999, but this produces some combinations of digits that contain duplicates of the same digit (for example, 099). Online calculator combinations without repetition. Everyone who receives the link will be able to view this calculation, Copyright PlanetCalc Version: Our ncr calculator uses this formula for the accurate & speedy calculations of all the elements of the dataset. . We only have one of each item. The copy-paste of the page "Combinations with Repetition" or any of its results, is allowed as long as you cite dCode! By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. The procedure is: Get all the {2 element} unique combination for each set. Please send us a message via Facebook or Instagram, so we can build this feature for you. Permutations generator. / (n-r)! an idea ? It is a unique way in which several objects could be ordered or chosen. 2 3 5 And, you always select the least digit first for e and f also, with the additional condition that d < e < f. List out the first sequence, 012, 013, 014, 015, 016, 017, 018, 019. Different ways to count Combination with repetitions? In a separate tab I want to generate a list of non-repeating combinations, order does not matter, and I want to run this list in varying string length (1x, 2x, 3x, 4x, .) There are a lot of use cases for a combination generator: Do you have more examples of use cases for a combination generator? Boolean [] GenerateCombination ( int n, Random randomSource) Generate a random combination, without repetition, by randomly selecting some of N elements. You can also change the separator (character that separates the values in the concatenated string of values) Doesn't analytically integrate sensibly let alone correctly, Batch split images vertically in half, sequentially numbering the output files. . How do I align things in the following tabular environment. All (sorted): "A - 1 | A - 2 | B - 1 | B - 2". Such as 1,2,3,4,12,13,23,14,24,34,123,124,134,234,1234". Input variables and calculate The output columns are C, E, G, I & K. If we make 6 combinations then the 6th column would be M. The output should start from second row -> C2, E2, G2, I2, K2 (& M2 if we can go up to 6 combinations) The calculation uses the binomial coefficient: $$ C_n^k = \binom{n}{k} = \frac{n!}{k!(n-k)!} To use our combination calculator, you need to perform the following steps. nCr = n! Permutation generator from n to m without. The total number of possible combinations, as shown in Combinatorics combinations, arrangements and permutations, is Combinatorics can introduce huge numbers, this limit secures the computation server. How to calculate the number of possible license plate using the formula for combinations with repetitions allowed? What is the purpose of this D-shaped ring at the base of the tongue on my hiking boots? Example 2: 2 girls will go to a party, if between the two, they have 4 pairs of fancy shoes, define the combination of shoes this two girls can wear. Browser slowdown may occur during loading and creation. Please, check our dCode Discord community for help requests!NB: for encrypted messages, test our automatic cipher identifier! I need help with generating a list of all possible combinations without repetition. x 18 = 6.2e8 elements. Permutation generator from n to m without. int n. Number of elements in the set. Permutation where a particular item is to be in the specified place, Round about Permutation when there are "n" objects they can be organized in (n-1) ways. How to count combinations with repetition? Except explicit open source licence (indicated Creative Commons / free), the "Combinations with Repetition" algorithm, the applet or snippet (converter, solver, encryption / decryption, encoding / decoding, ciphering / deciphering, translator), or the "Combinations with Repetition" functions (calculate, convert, solve, decrypt / encrypt, decipher / cipher, decode / encode, translate) written in any informatic language (Python, Java, PHP, C#, Javascript, Matlab, etc.) First you select a digit d from {0, 1, 2, 3, 4, 5, 6, 7, 8, 9}. Tool to generate combinations. # combinations = n! To avoid using Excel to create combinations. Free online combinations calculator and permutations calculator for Repetition isn't allowed because Susan can't be . Combinations without repetition of $$5$$ elements taken $$2$$ at a time: $$ab$$, $$ac$$, $$ad$$, $$ae$$, $$bc$$, $$bd$$, $$be$$, $$cd$$, $$ce$$ and $$de$$. You first select 0 for d, then 1, and so on until you get to 7. I checked almost every similar post in here but I couldn't figure out how I can do what I want. This JavaScript produces all 120 combinations. Solution: Then you select a digit f from (({0, 1, 2, 3, 4, 5, 6, 7, 8, 9}-d)-e). Here is how it works on example: $$. In the case of the combination the order of the elements does not matter. Normally there should be an index for each subset but since they are all the same length, the number of unique combinations will be the same so you can just reuse 4x the same index. Separate numbers by space, comma, new line or no-space. Disturbing. But Ads helps us to cover costs and to keep tools free. Their count is: C k(n)= ( kn+k 1) = k!(n1)!(n+k1)! At 30 choose 5, the number of combinations is 142'506, but after filtering, it drops to 123'447 valid combinations. Cite as source (bibliography): Back to i = 2 How many five card hands can be drawn from a deck of 52 cards.